## Uniform flow across a mountain

*Details on the computation*

**Initialisation**
Vorticity: zero
Tracers: single tracer point at the centre of the domain
Computation: domain: X = (-3, ..., 3), Y = (-3, ..., 3)
no. of grid points from wall to wall: (129, 129)
boundary conditions: uniform flow in the x-direction
of velocity 1.67 [psi_top=2, psi_bottom=1]
standard Arakawa scheme used
rotation effects: f0 = +3. beta = 0, gamma = 0
bottom topography: circular mountain at the origin
with a half cosine profile.
max. height h_max = 0.4, radius R = 1.0
solver for streamfunction: NAG
viscosity: nu = 10^-3 (i.e. Re=1000 at T=0)
time step: dt = 0.05
final time: T = 5

<=== Uniform flow across a mountain

**
Jos van Geffen** --
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###### created: 21 April 1998

last modified: 26 May 2001